A spaceship is traveling through deep space to a space station and needs to make a course correction to go around a nebula. The captain orde

Question

A spaceship is traveling through deep space to a space station and needs to make a course correction to go around a nebula. The captain orders the ship to travel 2.3 106 kilometers before turning 70° and traveling 1.5 106 kilometers to reach the space station. If the captain had not ordered a course correction, what would have been the magnitude and direction of the path of the spaceship if it had traveled to the space station through the nebula?

in progress 0
Ben Gia 4 years 2021-08-02T19:16:10+00:00 1 Answers 47 views 0

Answers ( )

  1. thaiduong
    0
    2021-08-02T19:17:21+00:00
    Reply

    Answer:

    Explanation:

    Using the given values

    Let

    Px= 2.3 x 10^6, Py=0, Qx=1.5×10^6cos(70),

    Qy= 1.5×10^6sin(70)

    So let

    Hx= Px+Qx=2.813 x 10^6, Hy=Py+Qy=1.401 x 10^6

    Magnitude = √ ((2.813 x 10^6)^2+(1.401 x 10^6)^2)= 3.14 x 10^6

    To find direction

    tan စ = Hy/Hx = 1.401/2.813= 0.4980

    စ = 26.5°

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )