A NASA spacecraft measures the rate of at which atmospheric pressure on Mars decreases with altitude. The result at a certain altitude is:

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A NASA spacecraft measures the rate of at which atmospheric pressure on Mars decreases with altitude. The result at a certain altitude is:

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Dâu 5 years 2021-08-01T05:28:07+00:00 1 Answers 69 views 0

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  1. diemthu
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    2021-08-01T05:30:00+00:00
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    Complete Question

    A NASA spacecraft measures the rate R of at which atmospheric pressure on Mars decreases with altitude. The result at a certain altitude is: R = 0.0498 \ kPAkm^{-1} Convert R to kJ*m^{-4}

    Answer:

    The value  is       R = 0.0498 *10^{-3} \frac{kJ}{m^4}

    Explanation:

    From the question we are told that

       The altitude is  R = 0.0498 \ kPAkm^{-1}

    Generally  

         1 k PA = 1000 PA

    So  

       R = 0.0498 \frac{1000PA}{ km}

    Also  

       1 km  =  1000 m

       

    So  

         R = 0.0498 \frac{1000PA}{ 1000m}

    =>   R = 0.0498 \frac{1 PA}{ 1 m}

    Now  PA  is Pascal which is mathematically represented as

           PA = \frac{N}{m^2 }

    So

       R = 0.0498 \frac{\frac{N}{m^2} }{m}

        R = 0.0498 \frac{N}{m^3}

    Looking the unit we are arrive at we see that it contains  J  which is mathematically represented as

          J = N * m

    So  

      R = 0.0498 \frac{ N \frac{m}{m} }{m^3}

    =>  R = 0.0498 \frac{\frac{J}{m} }{m^3}

    =>  R = 0.0498 \frac{J}{m^4}

    Generally  

          1 J \to 1.0*10^{-3} kJ

          0.0498 J \to x kJ

    =>      x = \frac{0.0498 * 1.0*10^{-3}}{1}

    =>   0.0498 *10^{-3} kJ

    So

        R = 0.0498 *10^{-3} \frac{kJ}{m^4}

           

         

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