Find the magnetic field strength at 1.50 m from the center of the circular region (e.g., outside the electric-field region).

Question

Find the magnetic field strength at 1.50 m from the center of the circular region (e.g., outside the electric-field region).

in progress 0
Tài Đức 5 years 2021-07-31T06:01:58+00:00 1 Answers 13 views 0

Answers ( )

  1. binhan
    0
    2021-07-31T06:03:02+00:00
    Reply

    Answer:

    $ 1.81 \times 10^{-7} \ T$

    Explanation:

    Given :

    r = 1.50 m

    R = 1  m

    $\frac{dE}{dt}$ = $ 4.88 \times 10^{10} $  V / m s

    Therefore the displacement current is

    $ I_d = \epsilon_0. \frac{dE}{dt} . A $

        = $ \epsilon_0. \frac{dE}{dt} . \pi R^2 $

    Now according to law

    $ B= \frac{\mu_0I_d.\frac{dE}{dt}.\pi R^2}{2 \pi r}$

      = $ \frac{\mu_0I_d.\frac{dE}{dt}. R^2}{2 r}$

      = $ \frac{4 \pi \times 10^{-7} \times 8.85 \times 10^{-12} \times 4.88 \times 10^{10} \times 1^2}{2 \times 1.5} $

      = $ 1.81 \times 10^{-7} \ T$

    Therefore, the magnetic field strength at 1.50 m from the center of the ring is $ 1.81 \times 10^{-7} \ T$.

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )