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Given the displacement vector D = (2î − 6ĵ) m, find the displacement vector (in m) R so that D + R = −5Dĵ.
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Answer:
R = (-2î − 6ĵ + 10k^)m
Explanation:
We are given;
D = (2î − 6ĵ)
Now, we want to find R such that,
D + R = −5Dĵ
Plugging in (2î − 6ĵ) for D in the R equation gives;
(2î − 6ĵ) + R = -5(2î − 6ĵ)j
(2î − 6ĵ) + R = -10k + 0
This is because in vector multiplication, i × j = k and j × j = 0
Thus;
(2î − 6ĵ) + R = -10k
Making R the subject gives;
R = -2î − 6ĵ + 10k^
Thus, the displacement vector R is;
R = (-2î − 6ĵ + 10k^)m