Bailey was driving down the street on her motorcycle and reduced her velocity from 25 m/s to 15 m/s over a distance of 8 meters. What

Question

Bailey was driving down the street on her motorcycle and reduced her velocity from 25
m/s to 15 m/s over a distance of 8 meters. What is the magnitude of the motorcycle’s
acceleration during this time!

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Helga 5 years 2021-07-24T08:49:13+00:00 1 Answers 20 views 0

Answers ( )

  1. minhkhue
    0
    2021-07-24T08:50:52+00:00
    Reply

    Answer:

    a = – 25 m/s²

    Explanation:

    The magnitude of acceleration or deceleration of an object can be found by using the third equation of motion as follows:

    2as = Vf² – Vi²

    where,

    a = magnitude of acceleration = ?

    Vf = Final Velocity = 15 m/s

    Vi = Initial Velocity = 25 m/s

    s = distance traveled = 8 m

    Therefore,

    2a(8 m) = (15 m/s)² – (25 m/s)²

    a = (- 400 m²/s²)/(16 m)

    a = – 25 m/s²

    Here negative sign indicates deceleration

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