A pull back toy car accelerates for 1.8 seconds and covers 4 m while speeding up after being released from rest.

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Physics MichaelMet 4 years 2021-09-05T12:14:42+00:00 2021-09-05T12:14:42+00:00 1 Answers 11 views 0

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Captcha* Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )

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Neala · Answer 1 · 2021-09-05T12:16:40+00:00

Answer:

Acceleration, a = 2.47 seconds

Explanation:

Given the following data;

Time, t = 1.8 seconds

Distance = 4 meters

Initial velocity = 0 m/s (since it’s starting from rest)

To find the acceleration of the toy car, we would use the second equation of motion;

$S = ut + \frac {1}{2}at^{2}$

Where;

S represents the displacement or height measured in meters.

u represents the initial velocity measured in meters per seconds.

t represents the time measured in seconds.

a represents acceleration measured in meters per seconds square.

Substituting into the equation, we have;

Substituting into the formula, we have;

$4 = 0(1.8) + \frac {1}{2}*a*(1.8)^{2}$

$4 = 0 + \frac {1}{2}*a*3.24$

$4 = \frac {1}{2}*a*3.24$

Cross multiplying, we have;

$8 = 3.24a$

$a = \frac {8}{3.24}$

Acceleration, a = 2.47 seconds