A small 10.0 g ball is held to a slingshot that is stretched 6.0 cm. The spring constant is 2.0 × 102 N/m. a. What is the

Question

A small 10.0 g ball is held to a slingshot
that is stretched 6.0 cm. The spring
constant is 2.0 × 102 N/m.
a. What is the elastic potential energy
of the slingshot before it is
released?

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RuslanHeatt 4 years 2021-09-05T09:54:51+00:00 1 Answers 44 views 0

Answers ( )

  1. Neala
    0
    2021-09-05T09:56:41+00:00
    Reply

    Answer:

    0.36 J

    Explanation:

    PE = \frac{1}{2} kx^{2} \\PE = \frac{1}{2} (200 N/m)(0.06 m)^{2} \\PE = 0.36 J

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