A 1,500 kg car is at rest on a level track. The driver gives the engine gas and the car begins to accelerate forward. The car moves from 0 m

Question

A 1,500 kg car is at rest on a level track. The driver gives the engine gas and the car begins to accelerate forward. The car moves from 0 m/s to 27 m/s in 8 sec. What is the acceleration of the car?

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Nho 4 years 2021-09-05T07:23:22+00:00 1 Answers 19 views 0

Answers ( )

  1. Dau
    0
    2021-09-05T07:25:11+00:00
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    Answer:

    3.375 m/s²

    Explanation:

    Using equation of motion:

    v = u + at

    Here, v = 27m/s & u = 0m/s & t = 8 sec

    Let the acceleration be a.

    => 27 = 0 + 8(a)

    => 27/8 = a

    => 3.375 m/s²

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