An object of mass 1.5 kg is moving forwards along the floor against an applied force of 40.0 N [backwards]. If the coefficient of kine

Question

An object of mass 1.5 kg is moving forwards along the floor against an applied force of
40.0 N [backwards]. If the coefficient of kinetic friction is 0.25, determine the
acceleration of the object.

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RuslanHeatt 4 years 2021-09-04T19:40:42+00:00 1 Answers 8 views 0

Answers ( )

  1. Orla
    0
    2021-09-04T19:42:01+00:00
    Reply

    Answer:

    The acceleration of the object is -29.12 m/s².

    Explanation:

    The acceleration of the object can be calculated by Newton’s second law:

    \Sigma F = ma

    - F - F_{\mu} = ma                        

    - F - \mu mg = ma                        

    Where:

    F: is the applied force = 40.0 N

    μ: is the coefficient of kinetic friction = 0.25

    m: is the mass of the object = 1.5 kg

    g: is the acceleration due to gravity = 9.81 m/s²

    a: is the acceleration =?

    a = \frac{- F - \mu mg}{m} = \frac{-40.0 N - 0.25*1.5 kg*9.81 m/s^{2}}{1.5 kg} = -29.12 m/s^{2}

    The minus sign is because means that the object is decelerating due to the applied force and the friction.  

    Therefore, the acceleration of the object is -29.12 m/s².

    I hope it helps you!  

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