The orbital radius of the Earth (the average Earth-Sun distance) is 1.496 × 1011 m. Mercury’s orbital radius is 5.79 × 1010 m and Pluto’s is

Question

The orbital radius of the Earth (the average Earth-Sun distance) is 1.496 × 1011 m. Mercury’s orbital radius is 5.79 × 1010 m and Pluto’s is 5.91 × 1012 m. Calculate the time required for light to travel from the Sun to each of the three celestial bodies

in progress 0
Ngọc Khuê 5 years 2021-09-02T21:13:14+00:00 1 Answers 193 views 0

Answers ( )

  1. Dulcie
    0
    2021-09-02T21:14:40+00:00
    Reply

    Answer:

    Earth: t = 498.667\,s, Mercury: t = 193\,s, Pluto: t = 19700\,s

    Explanation:

    The light travels at a constant speed of approximately 3\times 10^{8} meters per second. The time (t), in seconds, required for light to travel a given distance is:

    t = \frac{x}{v_{l}} (1)

    Where:

    x – Travelled distance, in meters.

    v_{l} – Speed of light, in meters per second.

    Now, we calculate the time for light to travel to each planet:

    Earth (v_{l} = 3\times 10^{8}\,\frac{m}{s}, x = 1.496\times 10^{11}\,m)

    t = \frac{x}{v_{l}}

    t = 498.667\,s

    Mercury (v_{l} = 3\times 10^{8}\,\frac{m}{s}, x = 5.79\times 10^{10}\,m)

    t = \frac{x}{v_{l}}

    t = 193\,s

    Pluto (v_{l} = 3\times 10^{8}\,\frac{m}{s}, x = 5.91\times 10^{12}\,m)

    t = \frac{x}{v_{l}}

    t = 19700\,s

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )