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What is the speed of a 200-kilogram car that is driving with 2000 joules of kinetic energy? (SHOW ALL WORK)
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Answers ( )
Answer:
v ≈ 4.47
Explanation:
The Formula needed = KE =
m v²
Substitute with numbers known:
2000J =
× 200kg × v²
Simplify:
÷100 ÷100 (Divide by 100 on both sides)
2000J = 100 × v²
20 = v²
√ √ (Square root on both sides)
√20 = √v²
4.472135955 = v (Round to whatever the question asks)
v ≈ 4.47 (I rounded to 2 decimal places or 3 significant figures, as that is what it usually is)