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A horizontal spring is lying on a frictionless surface. One end of the spring is attached to a wall, and the other end is connected to a mov
Question
A horizontal spring is lying on a frictionless surface. One end of the spring is attached to a wall, and the other end is connected to a movable object. The spring and object are compressed by 0.065 m, released from rest, and subsequently oscillate back and forth with an angular frequency of 11.3 rad/s. What is the speed of the object at the instant when the spring is stretched by 0.048 m relative to its unstrained length
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Physics
3 years
2021-09-01T12:33:07+00:00
2021-09-01T12:33:07+00:00 1 Answers
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Answers ( )
Answer:
Explanation:
Given that:
angular frequency = 11.3 rad/s
Spring constant (k) =![Rendered by QuickLaTeX.com = \omega^2 \times m](https://documen.tv/wp-content/ql-cache/quicklatex.com-28145f89deee8951edde0da44cf5b188_l3.png)
k = (11.3)² m
k = 127.7 m
where;
According to the conservation of energies;
∴