A metal sphere of radius 10 cm carries a charge of 2.0 MicroCoulomb.What is the magnitude of the electric field 5.0 cm from the sphere’s sur

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A metal sphere of radius 10 cm carries a charge of 2.0 MicroCoulomb.What is the magnitude of the electric field 5.0 cm from the sphere’s surface?

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Nem 4 years 2021-08-25T04:56:17+00:00 1 Answers 40 views 0

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  1. Acacia
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    2021-08-25T04:57:34+00:00
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    Answer:

    E = 7200 J = 7.2 KJ

    Explanation:

    The electric field due to a sphere is similar to the electric field due to a point charge. It is calculated by the use of the following formula:

    E = \frac{kq}{r^2}\\

    where,

    E = Electric Field = ?

    k = Coulomb Constant = 9 x 10⁹ Nm²/C²

    q = charge on sphere = 2 μC = 2 x 10⁻⁶ C

    r = distance from the center of the sphere to the location = 5 cm = 0.05 m

    Therefore,

    E = \frac{(9\ x\ 10^9\ Nm^2/C^2)(2\ x\ 10^{-6}\ C)}{(0.05\ m)^2}

    E = 7200 J = 7.2 KJ

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )