A negative charge of – 0.0005 C exerts an attractive force of 7.0 N on a second charge that is 10 m away. What is the magnitude of the secon

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A negative charge of – 0.0005 C exerts an attractive force of 7.0 N on a second charge that is 10 m away. What is the magnitude of the second charge?

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Nguyệt Ánh 5 years 2021-08-17T15:55:48+00:00 1 Answers 27 views 0

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  1. ngockhue
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    2021-08-17T15:57:27+00:00
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    Answer:

    the magnitude of the second charge is 0.000156 C.

    Explanation:

    Given;

    mangitude of the first charge, q₁ = 0.0005 C

    attractive force between the two charges, F = 7.0 N

    distance between the two charges, r = 10 m

    let the magnitude of the second charge = q₂

    The magnitude of the second charge is calculated by applying Coulomb’s law;

    F = \frac{kq_1q_2}{r^2}

    Where;

    K is Coulomb’s constant = 9 x 10⁹ Nm²/C²

    q_2 = \frac{Fr^2}{kq_1} \\\\q_2 = \frac{7 \times \ 10^2}{(9\times 10^9)(0.0005)} \\\\q_2 = 0.000156 \ C

    Therefore, the magnitude of the second charge is 0.000156 C.

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