A solenoid coil 10cm long has 40 turns cm-1. The current rises from zero to its maximum value of 5.0000 A and 0000.01s when the switch is cl

Question

A solenoid coil 10cm long has 40 turns cm-1. The current rises from zero to its maximum value of 5.0000 A and 0000.01s when the switch is closed. Find the energy stored in magnetic field if the area of cross section of solenoid be 28 centimeter square.

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Yến Oanh 5 years 2021-08-16T22:22:55+00:00 1 Answers 62 views 1

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  1. thienan
    0
    2021-08-16T22:24:00+00:00
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    Answer:

    Explanation:

    Energy stored in a solenoid per unit volume = B₀² / (2μ₀)

    B₀= μ₀ n I₀

    n is no of turns per unit length .

    Energy stored in a solenoid per unit volume = ( μ₀ n I₀)² / (2μ₀)

    =μ₀n²I₀²/2

    n = 40 turns / cm = 40 x 100 turns per meter.

    I₀ = 5000A .

    Putting the values

    Energy stored in a solenoid per unit volume

    = 4π x 10⁻⁷ x 40 x 10² x 5000² /2

    = 1256 J/ m³

    Volume of solenoid = cross sectional area  x length

    = 28 x 10⁻⁴ x .10 = 2.8 x 10⁻⁴ m³

    Total energy stored = 1256  J / m³ x 2.8 x 10⁻⁴ m³

    = .35 J .

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