If the effort distance = 8 meters and the resistance distance = 1/2 meter. How much force does this man have to apply to lift the 1 ton (200

Question

If the effort distance = 8 meters and the resistance distance = 1/2 meter. How much force does this man have to apply to lift the 1 ton (2000 N) weight?

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Neala 3 years 2021-08-14T03:08:21+00:00 1 Answers 9 views 0

Answers ( )

  1. thongdat2
    0
    2021-08-14T03:09:38+00:00
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    Answer:

    Explanation:

    Effort x effort distance = load x resistance  distance

    effort distance = 8 m ,

    load = 2000N

    resistance distance = 1/2 m = 0.5 m

    Putting the values in the equation above

    effort x 8m = 2000N x .5

    effort = 2000 x 0.5 / 8

    = 125 N

    force required = 125 N .

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