A pressure of 7×10^5N/m is applied to all surfaces of a copper cube (of sides 25 cm) what is the fractional change in volume of a cube? ( fo

Question

A pressure of 7×10^5N/m is applied to all surfaces of a copper cube (of sides 25 cm) what is the fractional change in volume of a cube? ( for copper B= 14×10^10N/m)

in progress 0
Amity 5 years 2021-08-10T06:56:19+00:00 1 Answers 20 views 0

Answers ( )

  1. mocmien2
    0
    2021-08-10T06:57:48+00:00
    Reply

    Answer:

    The correct solution is “5\times 10^{-4} %”.

    Explanation:

    The given values are:

    Pressure,

    \Delta P=7\times 10^5 \ N/m

    for copper,

    B=14\times 10^{10} \ N/m

    As we know,

    The Bulk Modulus (B) = \frac{\Delta P}{-\frac{\Delta V}{V} }

    or,

    The decrease in volume will be:

    = (\frac{\Delta V}{V})\times 100 \ percent

    then,

    = \frac{\Delta P}{B}\times 100 \ percent

    On putting the values, we get

    = \frac{7\times 10^5}{14\times 10^{10}}\times 100 \ percent

    = 5\times 10^{-4} \ percent

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )