Imagine you are holding a box in your hand, the force required for you to hold the box with mass 4.54kg and you want to accelerate the box 2

Question

Imagine you are holding a box in your hand, the force required for you to hold the box with mass 4.54kg and you want to accelerate the box 2m/s2. Move the box in your hand a) upward vertically, b) downward vertically, and c) horizontally. Calculate the magnitudes of forces in the x and y direction.

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Cherry 4 years 2021-08-07T22:36:41+00:00 1 Answers 11 views 0

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  1. thugiang
    0
    2021-08-07T22:38:05+00:00
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    Answer:

    (a) Fₓ = 0 N

    F_y = 9.08 N

    (b)

    (a) Fₓ = 0 N

    F_y = 9.08 N

    (c) F_y = 0 N

    Fₓ = 9.08 N

    Explanation:

    The magnitude of the force will remain the same in each case, which is given as follows:

    F = ma (Newton’s Second Law)

    where,

    F = force = ?

    m = mass = 4.54 kg

    a = acceleration = 2 m/s²

    Therefore,

    F = (4.54 kg)(2 m/s²)

    F = 9.08 N

    Now, we come to each scenario:

    (a)

    Since the motion is in the vertical direction. Therefore the magnitude of the force in x-direction will be zero:

    Fₓ = 0 N

    For upward direction the force will be positive:

    F_y = 9.08 N

    (b)

    Since the motion is in the vertical direction. Therefore the magnitude of the force in x-direction will be zero:

    Fₓ = 0 N

    For upward direction the force will be negative:

    F_y = – 9.08 N

    (c)

    Since the motion is in the horizontal direction. Therefore the magnitude of the force in y-direction will be zero:

    F_y = 0 N

    Fₓ = 9.08 N

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )