A volume V= 2.48 L of an ideal nitrogen gas (N2) are at temperature T= 0.964°C and pressure p = 1.49 atm.

Question

A volume V= 2.48 L of an ideal nitrogen gas (N2) are at temperature T= 0.964°C and pressure p = 1.49 atm.

in progress 0
Nho 5 years 2021-08-05T04:53:43+00:00 1 Answers 17 views 0

Answers ( )

  1. Sapo1
    0
    2021-08-05T04:55:24+00:00
    Reply

    Complete question:

    A volume V= 2.48 L of an ideal nitrogen gas (N2) are at temperature T= 0.964°C and pressure p = 1.49 atm. Find the number of moles of the gas.

    Answer:

    The number of mole of the gas is 0.164 mol.

    Explanation:

    Given;

    volume of the ideal gas, V = 2.48 L

    temperature of the gas, T = 0.964 °C = 273K + 0.964 = 273.964 K

    pressure of the gas, P = 1.49 atm

    The number of moles of the gas is calculated by using ideal gas equation;

    PV = nRT

    where;

    n is the number of moles of the gas

    R is ideal gas constant = 0.082057 L.atm/mol.K

    n = \frac{PV}{RT} \\\\n = \frac{1.49 \ atm \ \times \ 2.48 \ L}{0.082057 \ L.atm/mol.K \ \ \times \ 273.964 \ K} \\\\n = 0.164 \ mol

    Therefore, the number of mole of the gas is 0.164 mol.

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )