Keesha is looking at a beetle with a magnifying glass. She wants to see an upright, enlarged image at a distance of 25 cm. The focal length

Question

Keesha is looking at a beetle with a magnifying glass. She wants to see an upright, enlarged image at a distance of 25 cm. The focal length of the magnifying glass is +5.0 cm. Assume that Keesha’s eye is close to the magnifying glass.
(a) What should be the distance between the magnifying glass and the beetle?
(b) What is the angular magnification?

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Sigridomena 5 years 2021-07-30T13:46:31+00:00 1 Answers 24 views 0

Answers ( )

  1. niczorrrr
    0
    2021-07-30T13:48:27+00:00
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    Answer:

    a)   p = 4.167 cm, b)   m = + 6

    Explanation:

    a) For this exercise we must use the equation of the constructor

              \frac{1}{f} = \frac{1}{p} + \frac{1}{q}

    where f is the focal length, p and q are the distance to the object and the image, respectively

    In this case the distance to the image q = 25 cm and the focal length is f = 5.0 cm

    Since the object and its image are on the same side of the lens, the distance to the image by the sign convention must be negative.

           \frac{1}{p } = \frac{1}{f} - \frac{1}{q}

          \frac{1}{p} = \frac{1}{5} - \frac{1}{-25}

          \frac{1}{ p} = 024

          p = 4.167 cm

     

    b) angular magnification

         m = h ’/ h = – q / p

         m = – (-25) /4.167

         m = + 6

    the positive sign indicates that the image is straight and enlarged

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