A closely wound, circular coil with radius 2.80 cm has 790 turns. Part A What must the current in the coil be if the magnetic field at the c

Question

A closely wound, circular coil with radius 2.80 cm has 790 turns. Part A What must the current in the coil be if the magnetic field at the center of the coil is 0.0760 T

in progress 0
Thiên Thanh 5 years 2021-07-28T03:55:08+00:00 1 Answers 30 views 0

Answers ( )

  1. MichaelMet
    0
    2021-07-28T03:56:56+00:00
    Reply

    Answer:

    I=11.1A

    Explanation:

    From the question we are told that:

    Radius R=2.80

    Turns N=790

    Magnetic field B=0.0760

    Generally the equation for Magnetic field at the center of the coil is mathematically given by

     B=\frac{\mu NI}{2r}

     0.076=\frac{4\p*10^-^7*790*I}{2*0.028}

     I=\frac{0.076*2*0.028}{4\p*10^{-7}*790}

     I=11.1A

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )