An archer shoots an arrow horizontally at a target 12 m away. The arrow is aimed directly at the center of the target, but it hits 51 cm low

Question

An archer shoots an arrow horizontally at a target 12 m away. The arrow is aimed directly at the center of the target, but it hits 51 cm lower. What was the initial speed of the arrow?

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Nguyệt Ánh 3 years 2021-07-22T15:16:29+00:00 1 Answers 17 views 0

Answers ( )

  1. ngockhue
    0
    2021-07-22T15:18:10+00:00
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    Answer:

    Your mistake was to use v0 in the calculation of height. The problem statement says the arrow was shot horizontally, so the initial speed in the vertical direction is zero, while the initial speed in the horizontal direction is v0. The vertical drop is

    d = (1/2)gt2 = 0.56 m

    Get t from this, and then set

    v0t = 15 m [i.e. the horizontal travel distance at constant speed],

    and then get v0 knowing t.

    (1/2)(9.8)t2 = 0.56

    t = √[2(0.56)/9.8] s ≅ 0.338 s

    v0t = 15 m

    v0 = (15 m)/(0.338 s) ≅ 44.4 m/s in the horizontal direction, with no initial vertical velocity

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