A capacitor stores 7.77 x 10-7 J of energy when 4.29 x 10-8 C of charge is on the plates. What is the vo

Question

A capacitor stores 7.77 x 10-7 J of

energy when 4.29 x 10-8 C of

charge is on the plates. What is the

voltage across the capacitor?

[?] V

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Lệ Thu 5 years 2021-07-19T13:42:29+00:00 1 Answers 37 views 0

Answers ( )

  1. Sigrid
    0
    2021-07-19T13:44:21+00:00
    Reply

    Answer: 36.22\ V

    Explanation:

    Given

    Energy in a capacitor E=7.77\times 10^{-7}\ J

    Charge Q=4.29\times 10^{-8}\ C

    Energy of a capacitor is given by

    E=\dfrac{1}{2}CV^2=\dfrac{1}{2}QV\quad [\text{Q=CV}]

    Insert the values

    E=\dfrac{1}{2}QV\\\\\Rightarrow 7.77\times 10^{-7}=\dfrac{1}{2}\times 4.29\times 10^{-8}\times V\\\\\Rightarrow V=3.622\times 10\\\\\Rightarrow V=36.22\ V

    Thus, the voltage around the capacitor is 36.22\ V

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