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A remote ranch has a cylindrical water storage tank. It has a vertical central axis, a diameter of 24 ft, the sides are 5 ft high. The depth
Question
A remote ranch has a cylindrical water storage tank. It has a vertical central axis, a diameter of 24 ft, the sides are 5 ft high. The depth of this water is 4 ft. How much work (in ft-lb) would be required to pump all of the water over the upper rim?
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Physics
3 years
2021-07-18T17:51:11+00:00
2021-07-18T17:51:11+00:00 1 Answers
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Answers ( )
Answer:
Explanation:
From the given information:
The diameter of the pool = 24 ft
The radius will be = 24 ft/2 = 12 ft
The volume of water V = πr²(Δx)
V = π× 12²×(Δx)
V = 144π(Δx)
Le’s assume water weighs 62.5 lb/ft³;
Then:
the Force (F) will be:
= 144π(Δx) * 62.5
= 9000πΔx lb
Also, the side of cylindrical water = 5 ft while its depth = 4ft
As such, each slide of water d = 5 – x, and the region is between 0 and 4.
∴
The required work is: