The speed of a 2.0-kg object changes from 30 m/s to 40 m/s during a 5.0-second time interval. During this same time interval, the vel

Question

The speed of a 2.0-kg object changes from 30 m/s to 40 m/s during a 5.0-second time interval.
During this same time interval, the velocity of the object changes its direction by 90°. What is the
magnitude of the average total force acting on the object during this time interval?
a. 30 N
b. 20 N
c. 15 N
d. 40 N
e. 10 N
Which is the correct answer?

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Bơ 5 years 2021-07-18T09:45:07+00:00 1 Answers 317 views 0

Answers ( )

  1. Nick
    0
    2021-07-18T09:46:52+00:00
    Reply

    Answer:

    F = 2 * 30 / 5 = 12 N to stop forward motion

    F = 2 * 40 / 5 = 16 N to accelerate to 90 degrees

    (12^2 + 16^2)^1.2 = 20 N   average force applied

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