The lamps in circuit drawn below are all identical, Each of the cells have a potential difference of 1.5 volts What is the potential differe

Question

The lamps in circuit drawn below are all identical, Each of the cells have a potential difference of 1.5 volts What is the potential difference across the 3 cells that are joined in series

in progress 0
King 3 years 2021-07-17T12:34:54+00:00 1 Answers 2 views 0

Answers ( )

    0
    2021-07-17T12:36:49+00:00

    Answer:

    4.5V

    Explanation:

    In a arrangement of cells, the cells could be joined end to end(series) or to a common junction (parallel).

    When cells are joined in series, the total emf of the cell is the sum of the individual emf of all the cells.

    Hence;

    Total emf = 1.5V + 1.5V + 1.5 V = 4.5 Volts

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )