The amount of work required to increase the distance between -6μC and 4μC from 6 cm to 18 cm will be

Question

The amount of work required to increase the distance between -6μC and 4μC from 6 cm to 18 cm will be

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Thiên Ân 5 years 2021-07-16T15:54:46+00:00 1 Answers 6670 views 1

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  1. giabao
    -2
    2021-07-16T15:56:44+00:00
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    Answer:

    W = 1.8 J

    Explanation:

    The amount of work required to move the given charges can be found by using the following formula:

    W = \frac{kq_1q_2}{\Delta r} \\\\

    where,

    W = Work done = ?

    k = Colomb’s constant = 9 x 10⁹ Nm²/C²

    q₁ = magnitude of first charge = 6 μC = 6 x 10⁻⁶ C

    q₂ = magnitude of second charge = 4 μC = 4 x 10⁻⁶ C

    Δr = change in distance = 18 cm – 6 cm = 12 cm = 0.12 m

    Therefore,

    W = \frac{(9\ x\ 10^9\ Nm^2/C^2)(6\ x\ 10^{-6}\ C)(4\ x\ 10^{-6}\ C)}{0.12\ m}

    W = 1.8 J

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )