The Lamborghini Huracan has an initial acceleration of 0.85g. Its mass, with a driver, is 1510 kg. If an 80 kg passenger rode along, what wo

Question

The Lamborghini Huracan has an initial acceleration of 0.85g. Its mass, with a driver, is 1510 kg. If an 80 kg passenger rode along, what would the car’s acceleration be?​

in progress 0
Philomena 4 years 2021-07-15T15:01:55+00:00 2 Answers 195 views 0

Answers ( )

  1. thanhcong
    0
    2021-07-15T15:03:02+00:00
    Reply

    Answer:

    uuuujjht

    Explanation:

    gfthhmklkooojji

  2. RobertKer
    0
    2021-07-15T15:03:39+00:00
    Reply

    Answer:

    7.9 \frac{m}{s^{2} }

    Explanation:

    Take the fact that mass is inversely proportional to accelertation:

    m ∝ a

    Therefore m = a, but because we are finding the change in acceleration, we would set our problem up to look more like this:

    \frac{m_{1} }{m_{2} } = \frac{a_{2} }{a_{1} } \\

    Using algebra, we can rearrange our equation to find the final acceleration, a_{2}:

    a_{2} = \frac{a_{1}*m_{1} }{m_{2} } \\

    Before plugging everything in, since you are being asked to find acceleration, you will want to convert 0.85g to m/s^2. To do this, multiply by g, which is equal to 9.8 m/s^2:

    0.85g * 9.8 \frac{m }{s^{2} } = 8.33 \frac{m }{s^{2} }

    Plug everything in:

    7.9 \frac{m }{s^{2} } = \frac{ 8.33\frac{m}{s^{2} }*1510kg }{1590kg}

    (1590kg the initial weight plus the weight of the added passenger)

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )