It takes 130 j of work to compress a certain spring 0.10m. (a) what is the force constant of this spring? To compress the spring an addition

Question

It takes 130 j of work to compress a certain spring 0.10m. (a) what is the force constant of this spring? To compress the spring an additional 0.10m, does it take 130

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Tryphena 5 years 2021-07-13T03:56:10+00:00 1 Answers 71 views 0

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  1. MichaelMet
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    2021-07-13T03:58:04+00:00
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    Answer:

    Explanation:

    The PE equation for a mass/spring system is

    PE=\frac{1}{2}kΔx² and filling in:

    130=\frac{1}{2}k(.10)^2 and

    k=\frac{2(130)}{(.10)^2} so

    k = 26000 N/m

    If the displacement from equilibrium changes more, the PE needed to compress it will also change.

    PE=\frac{1}{2}(26000)(.20)^2 gives us that

    PE = 520J

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