A 90.0-kg mail bag hangs by a vertical rope 3.5 m long. A postal worker then displaces the bag to a position 2.0 m sideways from its origina

Question

A 90.0-kg mail bag hangs by a vertical rope 3.5 m long. A postal worker then displaces the bag to a position 2.0 m sideways from its original position, always keeping the rope taut. (a) What horizontal force is necessary to hold the bag in the new position

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Orla Orla 4 years 2021-07-12T16:01:24+00:00 1 Answers 342 views 0

Answers ( )

  1. trungdung22
    0
    2021-07-12T16:02:49+00:00
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    Answer:

    615 N

    Explanation:

    If θ is the angle from vertical and T is the rope tension

    θ = arcsin (2.0 / 3.5) = 34.85°

    Summing vertical forces to zero

    Tcosθ – mg = 0

    T = 90.0(9.81) / cos34.85 = 1,075.85 N

    Summing horizontal forces to zero

    F – Tsinθ = 0

    F = 1075.85sin34.85 = 1075.85(2.0/3.5) = 614.772… ≈ 615 N

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )