The extraction of iron from ore is represented by the chemical reaction equation. Fe2O3 + 3CO → 2Fe + 3CO2 Calculate the mass of

Question

The extraction of iron from ore is represented by the chemical reaction equation.
Fe2O3 + 3CO → 2Fe + 3CO2
Calculate the mass of carbon (II) oxide required for the reduction of 40 kg of iron (III) oxide

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Khoii Minh 5 years 2021-07-11T07:46:50+00:00 1 Answers 16 views 0

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    2021-07-11T07:47:55+00:00

    Answer:

    21 Kg of CO.

    Explanation:

    The balanced equation for the reaction is given below:

    Fe₂O₃ + 3CO —> 2Fe + 3CO₂

    Next, we shall determine the masses of Fe₂O₃ and CO that reacted from the balanced equation. This can be obtained as illustrated below:

    Molar mass of Fe₂O₃ = (56×2) + (16×3)

    = 112 + 48

    = 160 g/mol

    Mass of Fe₂O₃ from the balanced equation = 1 × 160 = 160 g

    Molar mass of CO = 12 + 16 = 28 g/mol

    Mass of CO from the balanced equation = 3 × 28 = 84 g

    SUMMARY:

    From the balanced equation above,

    160 g Fe₂O₃ required 84 g of CO.

    Finally, we shall determine the mass of of CO required for the reduction of 40 kg of Fe₂O₃. This can be obtained as follow:

    From the balanced equation above,

    160 g Fe₂O₃ required 84 g of CO.

    Therefore, 40 Kg of Fe₂O₃ will require = (40 kg × 84 g) / 160 g = 21 Kg of CO.

    Thus, 21 Kg of CO is required for the reaction.

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