What is the molality of a solution of Fe(ClO3), in water that freezes at -2.72°C?

Question

What is the molality of a solution of Fe(ClO3), in water that freezes at -2.72°C?

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Khoii Minh 4 years 2021-09-03T10:11:04+00:00 1 Answers 66 views 0

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  1. thongdat2
    0
    2021-09-03T10:12:50+00:00
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    Answer:

    0.366m = Molality of the solution

    Explanation:

    To solve this question we must know the addition of a solute produce decreasing in freezing point regard to the pure solvent. The equation is:

    ΔT = m*Kf*i

    Where ΔT is change in freezing point

    (As freezing point of water is 0°C, the ΔT is 2.72°C)

    Kf is freezing point depression constant = 1.86°C/m for water

    i is Van’t Hoff factor. The number of ions produced when 1 mole of the salt is dissolved = 4 ions for Fe(ClO₃)₃, Fe³⁺ and 3 ClO₃⁻ ions

    m is molality of the solution.

    Replacing:

    2.72°C = m*1.86°C/m*4

    0.366m = Molality of the solution

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