Consider the oxidation of sodium metal to sodium oxide described by the balanced equation: 4 Na + O2 → 2 Na2O. What is the theoretical

Question

Consider the oxidation of sodium metal to sodium oxide described by the balanced equation:
4 Na + O2 → 2 Na2O. What is the theoretical yield of Na2O in grams from 9.0 mol of O2?

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Maris 4 years 2021-08-24T12:10:29+00:00 1 Answers 44 views 0

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  1. Dulcie
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    2021-08-24T12:11:40+00:00
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    Answer:

    1116g

    Explanation:

    We’ll convert moles O2 -> moles of Na2O -> grams of Na2O.

    Based on our balanced equation, we have 1 mole of O2 for every 2 moles of Na2O. This is our mole to mole ratio.

    9 mol O2 x \frac{2 mol Na2O}{1 mol O2} = 18 mol Na2O

    We can convert mols -> grams using the molar mass of Na2O- 62g.

    18 mol Na2O x \frac{62g Na2O}{1 mol} = 1116g

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