8. What is the kinetic energy of a 0.02 kg bullet that is traveling 300 m/s? Express your answer in joules.​

Question

8. What is the kinetic energy of a 0.02 kg bullet that is traveling 300 m/s? Express your answer in joules.​

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Euphemia 3 years 2021-08-19T11:07:34+00:00 1 Answers 28 views 0

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  1. Nick
    0
    2021-08-19T11:09:08+00:00
    Reply

    900J

    Explanation:
    Well, kinetic energy is expressed through the equation:
    KE
    =
    1
    2
    m
    v
    2

    m
    is the mass of the object in kilograms

    v
    is the velocity of the object in meters per second

    So, we plug in the values, which are
    m
    =
    0.02

    kg

    v
    =
    300

    m/s

    And we get,
    KE
    =
    1
    2
    ⋅
    0.02

    kg
    ⋅
    (
    300

    m/s
    )
    2

    =
    1
    2
    ⋅
    0.02

    kg
    ⋅
    90000

    m
    2
    /s
    2

    =
    900

    kg m
    2
    /s
    2

    =
    900J

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )