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What is the pressure of a car tire that had an initial pressure of 33.7 kPa but was heated from 98.4°C to 110.°C?
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Answers ( )
Answer:
34752.6 Pa.
Explanation:
Applying,
P/T = P’/T’…………… Equation 1
Where P = Initial Pressure, T = Initial Temperature, P’ = Final pressure, T’ = Final temperature.
make P’ the subject of the equation
P’ = (PT’/T)………….. Equation 2
From the question,
Given: P = 33.7 kPa = 33700 Pa, T = 98.4°C = (273+98.4) = 371.4 K, T’ = (110+273) = 383 K
Substitute these values into equation 2
P’ = (33700×383)/371.4
P’ = 34752.6 Pa.