A precipitate of lead(II) chromate can be formed using the reaction below. Pb(ClO3)2(aq) + Na2CrO4(aq) → PbCrO4(s) + 2 NaClO3(aq

A precipitate of lead(II) chromate can be formed using the reaction below.

Pb(ClO3)2(aq) + Na2CrO4(aq) → PbCrO4(s) + 2 NaClO3(aq)

A chemist prepared the following two solutions and mixed them together in a large flask.

Solution A: 88.0 grams of solid Pb(ClO3)2 dissolved in 200 mL of water
Solution B: 40.9 grams of solid Na2CrO4 dissolved in 350 mL of water
What was the limiting reagent in the reaction that occurred when the solutions were mixed together, and which reagent remained in the solution after the reaction had occurred?
A
Pb(ClO3)2 was the limiting reagent, and Na2CrO4 remained in the solution.

B
Na2CrO4 was the limiting reagent, and Na2CrO4 remained in the solution.

C
Pb(ClO3)2 was the limiting reagent, and Pb(ClO3)2 remained in the solution.

D
Na2CrO4 was the limiting reagent, and Pb(ClO3)2 remained in the solution.