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A gas with a volume of 250 mL at a temperature of 293K is heated to 324K. What is the new volume of the gas?
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Answers ( )
V2 = 276 ml
Explanation:
Given:
V1 = 250 ml V2 = ?
T1 = 293K. T2 = 324K
Here, we use Charles’s law:
V1/T1 = V2/T2
Solving for P2, we get
V2 = (T2/T1)V1
= (324K/293K)(250 ml)
= 276 ml