According to the following reaction, how many grams of hydrobromic acid are needed to form 24.7 grams of bromine? hydrobro

Question

According to the following reaction, how many grams of
hydrobromic acid are needed to form 24.7 grams of bromine?

hydrobromic acid (aq) —>hydrogen (g) + bromine (1)

…grams hydrobromic acid

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Huyền Thanh 4 years 2021-08-04T22:37:18+00:00 1 Answers 37 views 0

Answers ( )

  1. quangkhai
    0
    2021-08-04T22:38:42+00:00
    Reply

    Answer:

    25.1 g

    Explanation:

    Step 1: Write the balanced decomposition reaction

    2 HBr(aq) ⇒ H₂(g) + Br₂(l)

    Step 2: Calculate the moles corresponding to 24.7 g of Br₂

    The molar mass of Br₂ is 159.81 g/mol.

    24.7 g × 1 mol/159.81 g = 0.155 mol

    Step 3: Calculate the moles of HBr needed to produce 0.155 moles of Br₂

    The molar ratio of HBr to Br₂ is 2:1. The moles of HBr needed are 2/1 × 0.155 mol = 0.310 mol.

    Step 4: Calculate the mass corresponding to 0.310 moles of HBr

    The molar mass of HBr is 80.91 g/mol.

    0.310 mol × 80.91 g/mol = 25.1 g

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