Under the right conditions aluminum will react with chlorine to produce aluminum chloride. 2 Al + 3Cl2 -> 2 AlCl3 How many gr

Question

Under the right conditions aluminum will react with chlorine to produce aluminum chloride.
2 Al + 3Cl2 -> 2 AlCl3
How many grams of aluminum chloride can be produced when 157.0g of aluminum react with excess chlorine?
Answer:775.9 g AlCl3
but what the steps pls help

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bonexptip 5 years 2021-08-02T20:18:24+00:00 1 Answers 22 views 0

Answers ( )

  1. thongdat2
    0
    2021-08-02T20:20:20+00:00
    Reply

    Answer:

    775.9 g

    Explanation:

    Step 1: Write the balanced equation

    2 Al + 3 Cl₂ ⇒ 2 AlCl₃

    Step 2: Calculate the mass corresponding to 157.0 g of Al

    The molar mass of Al is 26.98 g/mol.

    157.0 g × 1 mol/26.98 g = 5.819 mol

    Step 3: Calculate the moles of AlCl₃ produced from 5.819 moles of Al

    The molar ratio of Al to AlCl₃ is 2:2. The moles of AlCl₃ produced are 2/2 × 5.819 mol = 5.819 mol.

    Step 4: Calculate the mass corresponding to 5.819 moles of AlCl₃

    The molar mass of AlCl₃ is 133.34 g/mol.

    5.819 mol × 133.34 g = 775.9 g

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