16. A solution is made by dissolving 25 g of NaCl in enough water to make 1.0 L of solution. Assume the density of the solution is 1.0 g/cm3

Question

16. A solution is made by dissolving 25 g of NaCl in enough water to make 1.0 L of solution. Assume the density of the solution is 1.0 g/cm3. Calculate the molarity and molality of the solution.

in progress 0
Hải Đăng 5 years 2021-07-28T00:15:32+00:00 1 Answers 773 views 1

Answers ( )

  1. diemkieu
    0
    2021-07-28T00:17:12+00:00
    Reply

    Answer:

    The molarity will be “0.43 M” and molality will be “0.43 m“.

    Explanation:

    Given that:

    mass of NaCl,

    = 25 g

    Volume of solution,

    = 1 L

    Density of solution,

    = 1 gm/cm³

    Now,

    The weight of solvent will be:

    = Volume\times density

    = 1\times 1

    = 1 \ kg

    The mole of NaCl will be:

    = \frac{mass}{Molar \ mass}

    = \frac{25}{58.44}

    = 0.43

    hence,

    The molarity will be:

    = \frac{number \ of \ mole}{Volume \ of \ solution}

    = \frac{0.43}{1}

    = 0.43 \ M

    The molality will be:

    = \frac{mole \ of \ solute}{Weight \ of \ solvent}

    = \frac{0.43}{1}

    = 0.43 \ m

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )