Compound A reacts with alcoholic KOH to yield compound B which on ozonolyzises followed by the reaction with Zn/H2O gives methanal and propa

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Compound A reacts with alcoholic KOH to yield compound B which on ozonolyzises followed by the reaction with Zn/H2O gives methanal and propanal Compound A is

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Acacia 5 years 2021-07-26T02:59:23+00:00 1 Answers 304 views 0

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  1. mit
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    2021-07-26T03:00:51+00:00
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    Answer:

    1-chlorobutane

    Explanation:

    Given that :

    — The compound A is made to react with alcoholic KOH and produce compound B.

    — The compound B on Ozonolysis produces methanol as well as propanol

    The compound A should be a haloalkanes as treatment of haloalkanes with the alcoholic KOH, it will give alkene.

    $CH_3CH_2CH_2CH_2Cl+KOH( \text{alcohol}) \rightarrow CH_3CH_2CH=CH_2+KCl+H_2O$

    So, the compound B should be Butene

    Now the ozonolysis of the compound B or butene will give methanol and propanal as shown :

    $CH_3CH_2CH=CH_2 \rightarrow CH_2O+CH_3CH_2CHO$

    Therefore, the compound A is 1-chlorobutane.

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