A mixture of He, Ne, and N2 gases has a pressure of 1.943 atm. If the pressures of He and Ne are 0.137 atm and 0.566 atm, respectively, what

Question

A mixture of He, Ne, and N2 gases has a pressure of 1.943 atm. If the pressures of He and Ne are 0.137 atm and 0.566 atm, respectively, what is the partial pressure of N2 in the mixture?  A. 0.703 atm  B. 1.24 atm  C. 0.151 atm  D. 1.943 atm

in progress 0
Thiên Di 5 years 2021-07-19T07:12:22+00:00 1 Answers 4 views 0

Answers ( )

  1. thanhha
    0
    2021-07-19T07:14:16+00:00
    Reply

    Answer:

    The parcial pressure of N₂ in the mixture is 1.24 atm.

    Explanation:

    The pressure exerted by a particular gas in a mixture is known as its partial pressure. So, Dalton’s law states that the total pressure of a gas mixture is equal to the sum of the pressures that each gas would exert if it were alone:

    PT = PA + PB

    This relationship is due to the assumption that there are no attractive forces between the gases.

    In this case:

    PT=PHe + PNe + PN₂

    You know:

    • PT= 1.943 atm
    • PHe= 0.137 atm
    • PNe= 0.566 atm
    • PN₂= ?

    Replacing:

    1.943 atm= 0.137 atm + 0.566 atm + PN₂

    Solving:

    1.943 atm= 0.703 atm + PN₂

    1.943 atm – 0.703 atm= PN₂

    1.24 atm= PN₂

    The parcial pressure of N₂ in the mixture is 1.24 atm.

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )