A 1.0 g sample of propane, C3H8, was burned in calorimeter. The temperature rose from 28.5 0C to 32.0 0C and heat of combustion 10.5 kJ/g. C

Question

A 1.0 g sample of propane, C3H8, was burned in calorimeter. The temperature rose from 28.5 0C to 32.0 0C and heat of combustion 10.5 kJ/g. Calculate the heat capacity of the calorimeter apparatus in kJ/0C

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Latifah 5 years 2021-07-18T22:11:48+00:00 1 Answers 56 views 0

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  1. Dulcie
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    2021-07-18T22:13:34+00:00
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    Answer:

    A 1.0 g sample of propane, C3H8, was burned in the calorimeter.

    The temperature rose from 28.5 0C to 32.0 0C and the heat of combustion 10.5 kJ/g.

    Calculate the heat capacity of the calorimeter apparatus in kJ/0C

    Explanation:

    Heat of combustion = heat capacity of calorimeter * deltaT\\

    Given,

    The heat of combustion = 10.5kJ/g.

    deltaT = (32.0-28.5)^oC\\deltaT = 3.5^oC

    Substitute these values in the above formula to get the value of heat capacity of the calorimeter.

    deltaT =heat capacity of calorimeter * (change in temperature)\\10.5kJ/g = heat capacity of calorimeter * (3.5^oC)\\\\=>heat capacity of calorimeter = \frac{10.5kJ/g}{3.5^oC} \\=>heat capacity of calorimeter = 3.0 kJ/g.^oC

    Answer:

    The heat capacity of the calorimeter is 3.0kJ/g.^oC.

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