The elemental mass percent composition of succinic acid is 40.68% CC, 5.12% HH, and 54.19% OO. Determine the empirical formula of succinic a

Question

The elemental mass percent composition of succinic acid is 40.68% CC, 5.12% HH, and 54.19% OO. Determine the empirical formula of succinic acid.

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Trúc Chi 5 years 2021-07-13T03:26:32+00:00 1 Answers 80 views 0

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  1. thuthao
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    2021-07-13T03:27:38+00:00
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    Answer:

    C2H3O2

    Explanation:

    Empirical formula is defined as the simplest whole-number ratio of atoms present in a molecule. To solve this question we need to convert the percentage of each atom to moles using molar mass. With the moles of each atom we can find the ratio:

    Moles C -Molar mass: 12.01g/mol-

    40.68g * (1mol/12.01g) = 3.387 moles C

    Moles H-Molar mass:1g/mol-:

    5.12g * (1mol/1g) = 5.12 moles H

    Moles O -Molar mass: 16g/mol-

    54.19g * (1mol/16g) = 3.387 moles O

    Ratio of atoms (Dividing in moles of C that are the lower number of moles):

    C = 3.387 moles C / 3.387moles C = 1

    H = 5.12moles H / 3.387moles C = 1.5

    O = 3.387moles O / 3.387 moles C = 1

    This ratio twice (To have only whole-numbers):

    C = 2

    H = 3

    O = 2

    Empirical formula of succinic acid:

    C2H3O2

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