The radius of a platinum atom is 139 pm. How many platinum atoms would have to be laid side by side to span a distance of 1.39 mm?

Question

The radius of a platinum atom is 139 pm. How many platinum atoms would have to be laid side by side to span a distance of 1.39 mm?

in progress 0
Vodka 5 years 2021-07-13T03:23:47+00:00 1 Answers 203 views 0

Answers ( )

  1. Thunguyet
    0
    2021-07-13T03:25:02+00:00
    Reply

    Answer:

    5×10⁶ atoms of platium have to be laid side by side

    Explanation:

    1 atom of platium has a radius of 139pm = 139×10⁻¹²m. The distance that occupies 1 atom of platinum is 2 times its ratio:

    139×10⁻¹²m*2 = 2.78×10⁻¹⁰m

    Assuming there is no distance between to atoms of platinum, just its ratio. The amount of atoms necessary to occupy  1.39mm = 1.39×10⁻³m is:

    1.39×10⁻³m / 2.78×10⁻¹⁰m =

    5×10⁶ atoms of platium have to be laid side by side

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )