I want to create water out of 45.4 Liters of Oxygen at STP. How much water will I produce? STP: Standard Temperature and Pressure

Question

I want to create water out of 45.4 Liters of Oxygen at STP. How much water will I produce?
STP: Standard Temperature and Pressure
72g H2O
36g H20
9g H20
18g H20

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Bình An 4 years 2021-07-12T15:51:32+00:00 1 Answers 19 views 0

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  1. Eirian
    0
    2021-07-12T15:53:12+00:00
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    Answer:

    72.96 of water produce by 45.4 L of oxygen at STP.

    Explanation:

    H_2+\frac{1}{2}O_2\rightarrow H_2O

    1 mole of oxygen=22.4 L at STP

    \frac{1}{2}\mole of oxygen=22.4/2=11.2 L

    11.2 L of oxygen required to produce water=1 mole

    1 L of oxygen required to produce water=1/11.2 mole

    45.4 L of oxygen required to produce water=\frac{1}{11.2}\times 45.4

    45.4 L of oxygen required to produce water=\frac{45.4}{11.2}moles

    1 mole of water=18 g

    \frac{45.4}{11.2}moles of water=18\times \frac{45.4}{11.2}

    \frac{45.4}{11.2}moles of water=72.96 g

    Hence, 72.96 of water produce by 45.4 L of oxygen at STP.

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