Given 0.60 mol CO2, 0.30 mol CO, and 0.10 mol H20, what is the partial pressure of the CO if the total pressure of the mixture was 0.80 atm?

Question

Given 0.60 mol CO2, 0.30 mol CO, and 0.10 mol H20, what is the partial pressure of the CO if the total pressure of the mixture was 0.80 atm?

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Khánh Gia 4 years 2021-07-10T22:23:16+00:00 1 Answers 923 views 0

Answers ( )

  1. Dulcie
    1
    2021-07-10T22:25:07+00:00
    Reply

    Answer:

    Explanation:

    / means divided by

    * means multiply

    1. formula is

    partial pressure = no of moles(gas 1)/ no of moles(total)

    0.30 mol CO/0.60 mol CO2 + 0.30 mol CO + 0.10 mol H20 ->

    .3/(.6+.3+.1) =

    .3/1 =

    .3 =

    partial pressure of CO

    2.

    .3 * .8 atm = .24

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