A 25.0 mL sample of a saturated C a ( O H ) 2 solution is titrated with 0.029 M H C l , and the equivalence point is reached after 37.3 mL o

Question

A 25.0 mL sample of a saturated C a ( O H ) 2 solution is titrated with 0.029 M H C l , and the equivalence point is reached after 37.3 mL of titrant are dispensed. Based on this data, what is the concentration (M) of the hydroxide ion?

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Thiên Di 4 years 2021-07-10T12:49:02+00:00 1 Answers 1208 views 1

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  1. Acacia
    2
    2021-07-10T12:50:31+00:00
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    Answer:

    0.043 M

    Explanation:

    The reaction that takes place is:

    • Ca(OH)₂ + 2HCl → CaCl₂ + 2H₂O

    First we calculate how many HCl moles reacted, using the given concentration and volume required to reach the equivalence point:

    • 0.029 M HCl * 37.3 mL = 1.0817 mmol HCl = 1.0817 mmol H⁺

    As 1 mol of H⁺ reacts with 1 mol of OH⁻, in the 25.0 mL of the Ca(OH)₂ sample there are 1.0817 mmoles of OH⁻.

    With that in mind we can calculate the hydroxide ion concentration in the original sample solution, using the calculated number of moles and given volume:

    • 1.0817 mmol OH⁻ / 25.0 mL = 0.043 M

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )