giúp em câu a bài 9 ạ

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giúp em câu a bài 9 ạ

giup-em-cau-a-bai-9-a

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Ben Gia 5 years 2020-11-30T14:28:37+00:00 1 Answers 46 views 0

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  1. Orla
    0
    2020-11-30T14:29:56+00:00
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    $x \geq 0 ; x \neq 1$

    $M=\dfrac{3x+\sqrt{9x}-3}{x+\sqrt{x}-2}-\dfrac{\sqrt{x}+1}{\sqrt{x}+2}+\dfrac{\sqrt{x}-2}{1-\sqrt{x}}\\=\dfrac{3x+3\sqrt{x}-3}{(\sqrt{x}+2)(\sqrt{x}-1)}-\dfrac{x-1}{(\sqrt{x}+2)(\sqrt{x}-1)}-\dfrac{x-4}{(\sqrt{x}+2)(\sqrt{x}-1)}\\=\dfrac{3x+3\sqrt{x}-3-x+1-x+4}{(\sqrt{x}+2)(\sqrt{x}-1)}\\=\dfrac{x+3\sqrt{x}+2}{(\sqrt{x}+2)(\sqrt{x}-1)}\\=\dfrac{(\sqrt{x}+2)(\sqrt{x}+1)}{(\sqrt{x}+2)(\sqrt{x}-1)}\\=\dfrac{\sqrt{x}+1}{\sqrt{x}-1}$

     

     

     

     

     

     

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )