a) (x-1)^5=(x-1)^3 b) (X^5)^2=X^13 trên x^4 (x khác 0) c) (x-2)^6 = (x-2)^4 CÁC BẠN HỘ MÌNH VỚI MÌNH ĐANG CẦN GẤP

Question

a) (x-1)^5=(x-1)^3
b) (X^5)^2=X^13 trên x^4 (x khác 0)
c) (x-2)^6 = (x-2)^4
CÁC BẠN HỘ MÌNH VỚI MÌNH ĐANG CẦN GẤP

in progress 0
Tryphena 4 years 2020-10-13T11:03:56+00:00 1 Answers 86 views 0

Answers ( )

  1. Calantha
    0
    2020-10-13T11:05:44+00:00
    Reply

    $\begin{array}{l} a) \,(x-1)^5 = (x-1)^3\\ \Leftrightarrow (x-1)^5 – (x-1)^3 = 0\\ \Leftrightarrow (x-1)^3[(x-1)^2 – 1] = 0\\ \Leftrightarrow \left[\begin{array}{l}(x-1)^3 = 0\\(x-1)^2 – 1 =0\end{array}\right.\\ \Leftrightarrow \left[\begin{array}{l}x – 1 = 0\\(x-1)^2=1\end{array}\right.\\ \Leftrightarrow \left[\begin{array}{l}x =1\\x – 1 = 1\\x – 1 = -1\end{array}\right.\\ \Leftrightarrow \left[\begin{array}{l}x =1\\x =2\\x =0\end{array}\right.\\ b)\,(x^5)^2 = \dfrac{x^{13}}{x^4}\qquad (x \ne 0)\\ \Leftrightarow x^{10} = x^9\\ \Leftrightarrow x^{10} – x^9 = 0\\ \Leftrightarrow x^9(x – 1) = 0\\ \Leftrightarrow \left[\begin{array}{l}x^9 = 0\\x – 1 = 0\end{array}\right.\\ \Leftrightarrow \left[\begin{array}{l}x=0 \quad (loại)\\x =1 \quad (nhận)\end{array}\right.\\ c)\,(x-2)^6 = (x-2)^4\\ \Leftrightarrow (x-2)^6 – (x-2)^4 = 0\\ \Leftrightarrow (x-2)^4[(x-2)^2 – 1] = 0\\ \Leftrightarrow \left[\begin{array}{l}(x-2)^4 = 0\\(x-2)^2 – 1=0\end{array}\right.\\ \Leftrightarrow \left[\begin{array}{l}x-2 = 0\\(x-2)^2 =1\end{array}\right.\\ \Leftrightarrow \left[\begin{array}{l}x=2\\x – 2 = 1\\x – 2 = -1\end{array}\right.\\ \Leftrightarrow \left[\begin{array}{l}x=2\\x =3\\x =1\end{array}\right.\\ \end{array}$

     

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )